Summerhill, New York | |
---|---|
Coordinates: 42°39′21″N 76°18′27″W / 42.65583°N 76.30750°W | |
Country | United States |
State | New York |
County | Cayuga |
Government | |
• Type | Town Council |
• Town Supervisor | Charles Ripley (R) |
• Town Council | Members' List |
Area | |
• Total | 25.98 sq mi (67.30 km2) |
• Land | 25.86 sq mi (66.98 km2) |
• Water | 0.12 sq mi (0.32 km2) |
Elevation | 1,660 ft (506 m) |
Population (2010) | |
• Total | 1,217 |
• Estimate (2016)[2] | 1,168 |
• Density | 45.16/sq mi (17.44/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
FIPS code | 36-011-72037 |
GNIS feature ID | 0979536 |
Website | Town website |
Summerhill is a town in Cayuga County, New York, United States. The population was 1,217 at the 2010 census.[3] The town name is that of a location in Ireland. Summerhill is in the southeastern corner of the county and is northeast of Ithaca.
USCensusEst2016
was invoked but never defined (see the help page).