  Tsankov Island Location of Tsankov Island  Tsankov Island Tsankov Island (Antarctic Peninsula) | |
| Geography | |
|---|---|
| Location | Antarctica |
| Coordinates | 65°03′58″S 64°08′38″W / 65.06611°S 64.14389°W |
| Archipelago | Wilhelm Archipelago |
| Area | 9.48 ha (23.4 acres) |
| Length | 625 m (2051 ft) |
| Width | 216 m (709 ft) |
| Administration | |
| Administered under the Antarctic Treaty System | |
| Demographics | |
| Population | uninhabited |
Tsankov Island (Bulgarian: Цанков остров, romanized: Tsankov ostrov, IPA: [t͡sɐnˈkɔf ˈɔstrof]) is the mostly ice-covered island 625 m long in west-southwest to west-northeast direction and 216 m wide in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 9.48 ha.[1]
The feature is named after the dermatologist Nikolay Tsankov, participant in the 2010/11 and subsequent Bulgarian Antarctic campaigns.[1]
- ^ a b Tsankov Island. SCAR Composite Gazetteer of Antarctica