Vermont | |
|---|---|
| Town of Vermont | |
 Location in Dane County and the state of Wisconsin. | |
| Coordinates: 43°04′32″N 89°46′24″W / 43.07556°N 89.77333°W | |
| Country |  United States |
| State |  Wisconsin |
| County | Dane |
| Area | |
• Total | 35.8 sq mi (92.6 km2) |
| • Land | 35.8 sq mi (92.6 km2) |
| • Water | 0.0 sq mi (0.0 km2) |
| Elevation | 945 ft (288 m) |
| Population (2020) | |
• Total | 871 |
| • Density | 23.5/sq mi (9.1/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| Area code | 608 |
| FIPS code | 55-82525[2] |
| GNIS feature ID | 1729677[1] |
Vermont is a town[3] located in Dane County, Wisconsin, United States.[1] The population was 871 at the 2020 Census. The unincorporated communities of Elvers and Vermont are located in the town.
- ^ a b c "Town of Vermont". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved July 18, 2023.
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
- ^ "Towns" in Wisconsin perform most of the same functions as townships in many other states. see 'Wisconsin Blue Book 2022,' Town, pp 354-355